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δΈζTwo symbols, two rules. Fill the 6Γ6 grid with suns and moons so that every row and every column ends with exactly three of each, and never three of the same symbol in a row β horizontally or vertically. This is the classic binary-puzzle family (also seen as Binairo, Takuzu, or LinkedIn's Tango): trivially stated, surprisingly deep.
Today's verified daily is live β play it now.
| Rule | What it means |
|---|---|
| Equal counts | Every row and every column contains exactly three suns and three moons (on 6Γ6). |
| No triples | Three identical symbols never sit consecutively, in any row or column. |
| Unique solution | Each published board is machine-verified: one solution, reachable by deduction alone. |
Two identical symbols side by side must be capped on both ends by the opposite symbol β ββ forces πββπ. This is the fastest-firing rule in the family.
A gap between two identical symbols must hold the opposite one: β_β forces a moon in the middle, or three-in-a-row appears.
The moment a row holds its third sun, every empty cell in it is a moon. Combine with the no-triples check to finish lines in one sweep.
450 daily 6Γ6 boards (from 2026-08-24) plus 440 free-play boards in three difficulties, all with the same verification contract as every game on this site: exactly one solution, provably reachable without guessing, checked by machine before publication.
Fill the grid with two symbols so that each row and column contains an equal number of both, and no three identical symbols are adjacent horizontally or vertically. Some versions also forbid duplicate rows; this site's boards are uniquely solvable from the two core rules and the givens.
Same family. Binairo/Takuzu use 0s and 1s, LinkedIn's Tango uses suns and moons with extra = and Γ edge hints. The two core constraints β balanced counts and no three in a row β are shared across all of them.
Cap every adjacent pair: two identical symbols in a row force the opposite symbol on both ends. Together with filling the middle of an X_X gap, these two moves solve most of a 6Γ6 before counting is even needed.
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